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lordined5256
12.11.2019 •
Mathematics
According to a poll, 83% of california adults (418 out of 506 surveyed) feel that education is one of the top issues facing california. we wish to construct a 90% confidence interval for the true proportion of california adults who feel that education is one of the top issues facing california.
what is a point estimate for the true population proportion?
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Ответ:
A point estimate for the true population proportion is
and the 90% confidence interval is (0.8025, 0.8575)
Step-by-step explanation:
We have a large sample of people of size n = 506. Let X be the random variable that represents the number of adults who feel that education is one of the top issues facing California. We are interested in the unknown true proportion p of adults who feel that education is one of the top issues facing California. A point estimate for the true population proportion is given by
= X/n = 418/506 = 0.83, the standard deviation is given by
. Therefore, the 90% confidence interval for the true population proportion is
, i.e.,
, i.e.,
, (0.8025, 0.8575).
Ответ: