Mathematics: Aci is desired for the true average stray-load loss μ (watts) for a certain type of induction motor when the line current is held at 10 amps for a speed of 1500 rpm. assume that stray-load loss is normally distributed with σ = 2.1. (round your answers to two decimal places.) (a) compute a 95% ci for μ when n = 25 and sample mean = 58.3. (b) compute a 95% ci for μ when n = 100 and sample mean = 58.3.

Aci is desired for the true average stray-load loss

Ksouth13

08.01.2022

Step-by-step explanation:

Given that X stray load loss is normal with population std dev = 2.1

Since population std deviation is known we can use Z critical values for finding out confidence intervals

For 95% confidence interval we have formula as

Confidence interval 95% = $(\bar x-1.96(\frac{\sigma}{\sqrt{n} } ),\bar x+1.96(\frac{\sigma}{\sqrt{n} } )$

a) Substitute here for x bar = 58.3 and sigma = 2.1,n=25

Confidence interval = $(58.3-1.96(\frac{2.1}{5},58.3+1.96(\frac{2.1}{5}) \\=(57.4768,59.1232)\\=(57.48, 59.12)$

b) NOw we substitute sample size n =100, for same mean and std dev.

Confidence interval = $(58.3-1.96(\frac{2.1}{10},58.3+1.96(\frac{2.1}{10}) \\=(57.8884,58.7116)\\=(57.89, 58.71)$

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nook4boo

29.06.2022

Step-by-step explanation:

144/36=4

4 is the conversion factor

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