Acircle has its center at (−2, −3) and a radius of 3 units. what is the equation of the circle? (x + 2)2 + (y − 3)2 = 9 (x − 2)2 + (y − 3)2 = 3 (x + 2)2 + (y + 3)2 = 9 (x + 2)2 + (y + 3)2 = 3

The equation of a circle:

(h,k) - the coordinates of the center
r - the radius

(6,-1)
Multiply each equation by the value that makes the coefficients of xx opposite.(−3)⋅(2x+6y)=(−3)(6)(-3)⋅(2x+6y)=(-3)(6)(2)⋅(3x−2y)=(2)(20)(2)⋅(3x-2y)=(2)(20)Simplify.−6x−18y=−18-6x-18y=-186x−4y=406x-4y=40Add the two equations together to eliminate xx from the system.Divide each term by −22-22 and simplify.Tap for more steps...y=−1y=-1Substitute the value found for yy into one of the original equations, then solve for xx.Tap for more steps...x=6x=6The solution to the independent system of equations can be represented as a point.(6,−1)