Mathematics: Acircle with center (4 -3) contain the point (9,-3). what is an equation of the circle

I tried and it just says zero, Try that lol...

Acircle with center (4 -3) contain the point (9,-3).

Hailey1313131313

07.01.2022

$\large\boxed{(x-4)^2+(y+3)^2=25}$

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the center (4, -3) and the point on the circle (9, -3).

The length of radius is equal to the distance between a center and an any point on a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Susbtitute:

$r=\sqrt{(9-4)^2+(-3-(-3))^2}=\sqrt{5^2+0^2}=\sqrt{5^2}=5$

The center (4, -3) → h = 4, k = -3.

Finally we have:

$(x-4)^2+(y-(-3))^2=5^2\\\\(x-4)^2+(y+3)^2=25$

0,0(0 оценок)