Aclassroom of children has 16 boys and 19 girls in which five students are chosen to do presentations. what is the probability that at least four boys are chosen?

Total number of children = 16 + 19 = 35
Total number of boys = 16
Total number of girls = 19

Favorable outcomes = , G, BBBGB, BBGBB, BGBBB, G

P(at least 4 boys) = (16/35)(15/34)(14/33)(13/32)(12/31) + 4 (16/35)(15/34)(14/33)(13/32)(19/31) = 78/5797 + 494/5797 = 52/527

52/527

The answer to this is (8/2)^2 = 16