Acollege basketball coach has 12 players on his team. eight players are receiving scholarships, and four are not. the coach decides to select a starting lineup by selecting five names out of a bowl. the probability that 4 of 5 players selected are on scholarship is record answer to three decimal places

Solution: The given problem is a binomial distribution.

The probability that a team member receives a scholarship is

Therefore, the given problem follows binomial with n = 5 and p = 0.6667

Now the probability that 4 of 5 players selected are on scholarship is:

Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329