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kaziyahf2006
21.07.2019 •
Mathematics
Acombination lock requires three numbers from 1 to 25. how many combinations are possible? did you use the sum rule or the product rule? (note that although we use the term combination with locks, order matters.)
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Ответ:
The point is that numbers can be reused. 1 5 1 is a valid combination as is 4 4 4
20 * 5 * 1 is a valid combination as is 1 25 5
So the answer is 15625 "combinations" are possible <<<<< answer
Ответ:
Step-by-step explanation:
We have been given two numbers 7.7 and 7.9
whenever we need to find irrational number between any two given numbers
First thing we do is square both the numbers
Here![7.7^2=59.29=59.3](/tpl/images/0258/7036/b5cd7.png)
That is![\sqrt{59.3}=7.7](/tpl/images/0258/7036/ebc5b.png)
And![7.9^2=62.4](/tpl/images/0258/7036/eb0a0.png)
That is![\sqrt{62.4}=7.9](/tpl/images/0258/7036/e675d.png)
Hence, we can take the number in between 59.3 and 62.4 is 61
since,![\sqrt{61}=7.745966...\text{which is non-repeating and non-terminating term}](/tpl/images/0258/7036/cfb01.png)
Hence, 7.745966..... is the irrational number between 7.7 and 7.9