Acylinderical chemical drum is 220.5 cm long and the radius of the drum is 42 cm. calculate the cost of painting the drum akt the rate of rs. 0.15/cm

The surface area of the cylindrical drum of radius 21cm, height 50cm open at the top.

radius R = 42 cm

length L = 220.5 cm

bottom surface SB = 3.14 x R x R = 3.14 x 42 x 42 = 5539 square cm

top surface ST = 3.14 x R x R = 3.14 x 42 x 42 = 5539 square cm

bottom circumference BS = 3.14 x 2 x R = 3.14 x 2 x 42 = 264 cm

wall surface area WS = BS x L = 264 x 220.5 = 58212 square cm

whole outside surface area SB + ST + WS = 5539 + 5539 + 58212 = 69290 square cm

whole inside and outside surface area 69290 + 69290 = 138,590 square cm

the cost of painting the drum's inside and outside walls Rs. 0.15 x 138,590 = Rs20787

The answer to your question is This system of equations can not be solved. They do not cross.

Step-by-step explanation:

                               2x - 6y = 5             (I)

                                 x - 3y = -12           (II)

I.- Solve equation II for x

                                x = 3y - 12             (III)

2.- Substitute equation III on equation I

                            2(3y - 12) - 6y = 5

3.- Expand

                            6y - 24 - 6y = 5

                            6y - 6y = 5 + 24

                                    0 = 29

This system of equations can not be solved.