Mathematics: Adjust the window so you can find all of the points of intersection for the system of equations.what are the roots of the original polynomial equation? check all that apply.–606–438

You follow the order of operations, so first the two, so it would be -7+2x-6 then add -7 and -6, which equals to -13. Put the x first, so your answer would be 2x-13 so D...

Adjust the window so you can find all of the points

Ответ:

omar4538

15.03.2022

Mathematics

6,-4,3

Step-by-step explanation:

We are given that a polynomial

x^3+72=5x^+18x

x^3-5x^2-18x+72=0

We have to find the original roots of polynomial equation

Substitute -6 in the polynomial

Then , we get

(-6)^3-5(-6)^2-18(-6)+72

$-216-180+108+72\neq 0$

Therefore, it is not roots of the given polynomial.

Substitute x=0 then we get

$72\neq 0$

Hence, o is not a root of given polynomial.

Substitute x=6 then we get

(6)^3-5(6)^2-18(6)+72

216-180-108+72=288-288=0

Hence, 6 is a root of given polynomial because it satisfied the given polynomial.

Substitute x=-4 then we get

(-4)^3-5(-4)^2-18(-4)+72

-64-80+72+72=-144+144=0

Hence, -4 is a root of given polynomial .

Substitute x=3 then we get

(3)^3-5(3)^2-18(3)+72

27-45-54+72

99-99=0

Hence, 3 is a root of given polynomial.

Substitute x=8 then we get

(8)^3-5(8)^2-18(8)+72

$512-320-144+72\neq 0$

Hence, 8 is not a roots of given polynomial.

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Adjust the window so you can find all of the points of intersection for the system of equations.
what are the roots of the original polynomial equation? check all that apply.
–6
0
6
–4
3
8

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