Mathematics: Afarmer needs to enclose two adjacent rectangular pastures. how much fencing does the farmer need? write your answer as a mixed number. ( length - 50 5/8 yards. width - 30 2/9 yards. )

Afarmer needs to enclose two adjacent rectangular

Ответ:

ruchierosanp1n3qw

31.12.2021

The farmer needs 191 11/12 yards of fencing.

Given that a farmer needs to enclose two adjacent rectangular pastures, to determine how much fencing does the farmer need, knowing that the length of both fields combined is 50 5/8 yards, and the width of each of them (also including the division between them) is 30 2/9 yards, the following calculation must be made:

Both fields must be considered as the same rectangle, with an internal division the size of its width.

(2 x 50 5/8) + (3 x 30 2/9) = X (2 x 50,625) + (3 x 30,222) = X 101.25 + 90.66 = X 191.916 = X 191 11/12 = X

Therefore, the farmer needs 191 11/12 yards of fencing.

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Afarmer needs to enclose two adjacent rectangular pastures. how much fencing does the farmer need?

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Ответ:

fernandaElizondo

31.12.2021

Mathematics

the picture in the attached figure

Let

x--------> the length of the rectangular pastures

y--------> the width of the rectangular pastures

we know that

$x=50\frac{5}{8}yd\\ \\ y=30\frac{2}{9} yd$

Perimeter of the two adjacent rectangular pastures is equal to

P=2*(x+y)+y

$P=2*(50\frac{5}{8} +30\frac{2}{9} )+30\frac{2}{9} \\ \\ P=100\frac{10}{8} +90\frac{6}{9} \\ \\ P=100\frac{5}{4}+90\frac{2}{3}\\ \\ P=190\frac{(15+8)}{12} \\ \\ P=190\frac{23}{12} yd$