Afly undergoes a displacement of -5.80m while accelerating at -1.33m/s^2 for 4.22s. what was the initial velocity of the fly

3.94ms-¹

Step-by-step explanation:

s=-5.80, a=-1.33ms-², t=4.22s, u=?(where u is initial velocity)

v=displacement/time

v=s/t

v=-5.80/4.22

v=-1.37ms-¹

using this equation of motion

v=u+at

-1.37=u +(-1.33) x 4.22

making u the subject of the formula

u=v-at

u= -1.37 -(-1.33) x 4.22

u= -1.37 +1.33 x 4.22

u= -1.37+5.61

u= 3.94ms-¹

37.69    (≈ 38 ft²)

Step-by-step explanation:

2πr = 30.77

r = 30.77 / (2 * 3.14) = 4.9

half of free-throw circle area: πr² / 2 = (3.14 * 4.9²) / 2 = 37.69    (≈ 38 ft²)