Agame is played using one die. if the die is rolled and shows 5 5, the player wins $ 10 $10. if the die shows any number other than 5 5, the player wins nothing. if there is a charge of $ 2 $2 to play the game, what is the game's expected value?

The expected value is -$0.33

Step-by-step explanation: The expected value is calculated as:

E = ∑pₙxₙ

where xₙ is a given event (in this case winning 8$ or losing 2$) and pₙ is the probability for the event.

So in this you only win with one result in the dice, so the probability of winning is 1/6, and the probability of losing must be 5/6.

Then the expected value is:

E = 1/6*$8 - 5/6*$2 = $-0.33

Where I used the profit of $8 instead of $10, because you must pay $2 for play, and you win $10, the profit is ($10 - $2) = $8

Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

Here we need to substitute the different values of x , to get the different values of y.

Put x = -3 :-

Put x = -2 :-

Put x = -1 :-

Put x = 1 :-

Put x = 2 :-

Put x = 3 :-

Final table :-