Agroup of 10 people need to form a line. the line will consist of exactly 8 of the people. person x and person y have to be either fifth or sixth in line. how many different orders are possible?

N = 40,320

Step-by-step explanation:

To arrange 10 people to a line of 8 people.

The number of ways is n = 10P8.

But since the condition given states that 2 people must stay in two particular slots.

The number of possible arrangements becomes;

N = number of ways of arranging the remaining people × number of ways of arranging the other 2.

N = 8P6 × 2P2

N = 8!/2! × 2!

N = 20,160 × 2

N = 40,320 ways