Agroup of 42 people go to the zoo. the admission price is 6$ for adults and 3$ for kids. if the group spent 162$, how many adults and kids were in the group?

12 adults , 30 kids

Step-by-step explanation:

Let x represent the number of adult and y represent the number of kids , then from the first statement ;

x + y = 42 equation 1

For adults , the admission price is $6, the total cost for x adults will be 6x, Also , the admission price for kids is $3 ,this means that the total cost for y kids is 3y. The group spent $162 in all , this means that

6x + 3y = 162 equation 2

Solving the system of linear equation by substitution method , from equation 1 , make x the subject of the formula , that is

x = 42 - y equation 3

substitute x = 42 - y into equation 2 , we have

6(42 - y ) + 3y = 162

252 - 6y +3y = 162

252 - 3y = 162

Add  3y to both sides of the equation , we have

252 = 162 + 3y

subtract 162 from both sides of the equation

252 - 162 = 3y

90 = 3y

divide through by 3

Therefore : y = 30

substitute y = 30 into equation 3 ,that is

x = 42 - y

x = 42 - 30

x = 12

Therefore : there are 12 adults and 30 kids

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.