Ahardware store orders at most $2,500 worth of concrete and sand. the store needs to make a profit of at least $2,750 on the order. the possible combinations of concrete and sand for this order are given by this system of inequalities, where c = pounds of concrete and s = pounds of sand: 6c + 2s ≤ 2,500 4.50c + 3s ≥ 2,750 which graph's shaded region represents the possible combinations of concrete and sand for this order?

The below graph's shaded region represents the possible combinations of concrete and sand for this order

Step-by-step explanation:

Here, the system of inequality that represents the given situation is,

6c + 2s ≤ 2,500 --------(1)

4.50c + 3s ≥ 2,750 -------(2)

Where c = pounds of concrete,

s = pounds of sand

Now, The related equation of the above inequalities are,

6c + 2s = 2500

4.50c + 3s = 2750

By solving the above equations,

We get, ,

Thus, the intersection point of the inequalities =

Now, At (0,0) ,

inequality (1), 6×0 + 2×0≤ 2500 ⇒ 0 ≤ 2500 ( true)

Hence, the shaded region of inequality contains the origin.

Similarly, At (0,0), inequality (2) is false,

⇒ The shaded region of inequality (2) does not contain the origin.

Thus, By the above explanation we can plot the shaded region of the system of the given inequalities.

Ihave attached a screenshot with the diagramanswer: area = 30 in²explanation: area of the parallelogram can be calculated as follows: area = base * heightin the given, we have: base = ab = 10 inheight = ax  > we need to calculate that1- getting the height of the parallelogram (ax): we know that: ax is perpendicular on abmeasure angle dab = 30°this means that: measure angle xad = 90 - 30 = 60°now, in triangle xad, we have: measure angle x = 90°this means that this triangle is a right-angled triangle, therefore, we can apply the special trig functions to get the length of ax as follows: we know that: cos  θ = adjacent / hypotenusewe have: θ = 60°adjacent = ax that we want to findhypotenuse = ad = 6 inthis measn that: cos 60 = ax / 6ax = 6 * cos 60ax = 3 in2- getting the area of the parallelogram: area = base * heightarea = ab * axarea = 10 * 3area = 30 in²hope this : )