Marisolv06
20.12.2019 •
Mathematics
Ahelicopter leaves central airport and flies north at 180 mi/hr. twenty minutes later a plane leaves the airport and follows the helicopter at 330mi/hr. how long does it take the plane to overtake the helicopter
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Ответ:
Step-by-step explanation:
Let x represent the distance travelled by the helicopter and the plane.
Let t represent the time it takes the the helicopter to travel x miles
Speed of the helicopter is 180 miles per hour.
Distance travelled = speed × time
x = 180t
Twenty minutes later, a plane leaves the airport and follows the helicopter at 330mi/hr. Converting 20 minutes to hours, it becomes 20/60 minutes
Time taken for the plane to travel x miles is t - 20/60
x = 330(t - 20/60)
Before the plane overtakes the helicopter, they would have travelled equal distance. Therefore
330(t - 20/60) = 180t
330t - 110 = 180t
330t - 180t = 110
150t = 110
t = 110/150 = 0.73 hours
Ответ: