Ahigh school drama club is putting on their annual theater production there is a maximum of 800 tickets for the show the cost of the tickets are six dollars before the day of the show and nine dollars on the day of the show to meet the expenses of the shelf book club must sell at least $5000 worth of tickets

Step-by-step explanation:

a.) Let x be the number of tickets sold before the event and y the number of tickets sold on the day of the event. Then x + y =< 800 and 6x + 9y >= 5000. (b.) Suppose the club sold 440 tickets before the event, i.e. x = 440, maximum number of tickets remaining to be sold = 800 - 440 = 360. Maximum amount realized from the sales supposing all tickets were sold = 6(440) + 9(360) = 2640 + 3240 = $5880 which is greater than $5000. Therefore, it is possible for the club to sell enough additional tickets on the day of the show to meet the expenses of the show.

HOPE THIS HELPED ;3

42 + 14

Step-by-step explanation:

By counting the rows and columns, you'll notice the following:

1) The first pattern has 2 columns and increase by 1 column each time you move to the right.

2) The first pattern has 1 row and increase by 1 row each time move to the right.

3) To get to the 7th number, you will have to move to the right 6 times.

Hence,

1) if you start with 2 columns, and move 6 times to the right, each time adding one column you will end up with 2 + 6 = 8 columns

2) if you start with 1 row and move 6 times to the right, each time adding one row, you will end up with 1 + 6 = 7 rows

3) You will end up with a pattern with 8 columns and 7 rows and the number of dots will be 8 x 7 = 56.

If you work out all the answers, yo uwill see that only 42 + 14 gives you 56.