Ahmed competed in a competition that has a walking part and a biking part. The entire course was 15 miles. On average, Ahmed walks 3 mi/hr and bikes 12 mi/hr. Of the walking part of the competition took 1 hour longer than the biking part, how long did it take Ahmed to complete each part of the competition?

Walking part: 1hr 48mins

Biking part: 48 mins

Step-by-step explanation:

Total distance covered = 15 miles

Let the time taken for walking = w hours

Let the time taken for biking = b hours

Walking part took one hour longer than the biking part.

So, w = b + 1

// Distance covered, d1 = Speed * time taken

For walking part, d1 = 3 * w = 3w

But w = b + 1

So, d1 = 3(b + 1) = 3b + 3 miles

For biking part, d2 = 12 * b = 12b

d1 + d2 = Total distance covered

3b + 3 + 12b = 15

3b + 12b = 15 - 3

15b = 12

Divide both sides by 15

15b/15 = 12/15

b = 0.8 hour

But, w = b + 1

So, w = 0.8 + 1 = 1.8 hours

Ahmed took 0.8 hour (0.8 * 60min = 48mins) to complete the biking part and 1.8 hours (1hr + 48mins = 1hr 48mins) to complete the walking part

17.4 inches

Step-by-step explanation:

The mean is the average of all the numbers listed in the set. In order to find the mean you must add up all the numbers in the set and divide it by the number of numbers in the set.