Ahorizontal line through point -7,8

We don't know what you want because you didn't ask any question. Would you like to know the equation of such a line ? Well, every point on a horizontal line has the same 'y' coordinate. The point you mentioned has the 'y' coordinate of 8, so it's on the horizontal line (here comes the answer) . . . Y = 8 .

x=90 degrees, y=43 degrees

Step-by-step explanation:

The triangle ABC is an isosceles triangle with congruent sides AB and AC.  Therefore, the angles ABC and ACB are equal. Segment AD is the bisector of angle A (or BAC). The angle ACD is given as 47 degrees. So, angles ABC and ACB are 47 degrees each, since the point D is on side BC. The angle BAC is 180-2(47) degrees which is 86 degrees. Since AD is bisector of the angle BAC, BAD is 86/2=43 degrees . From the triangle BAD, angle of BDA is 180 - (the angle ABD + the angle BAD) = 180 -(47+43)=90 degrees. So x=90 and y=43 degrees.