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alanflores40
29.10.2019 •
Mathematics
Ahorse race has 13 entries. assuming that there are no ties, what is the probability that the four horses owned by one person finish first, second, third and fourth?
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Ответ:
How many ways all the horses can place = 13! = 6227020800
How many ways the first four places can place = 13*12*11*10 = 17160
Divide the second by the first and multiply by 100 for the probability as a percent:
(17160/6227020800)*100% ≈ 0.00027557319%
Ответ:
The solution would be like this for this specific problem:
4/13 * 3/12* 2/11 * 1/10 = 0.0014
So the probability that the four horses owned by one person finish first, second, third and fourth is 0.0014. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
Ответ:
-2x + 28
10x - 4
x - 13
-5x + 56
Step-by-step explanation: