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aderahd7352
08.07.2019 •
Mathematics
Airbags are manufactured by aces (a), best (b), and cool (c) at rates of 57%, 26% and 17%, respectively. airbags occasionally kill (k) passengers when they deploy in accidents. airbags made by aces, best, and cool do not kill people at rates of 99%, 96%, and 87%, respectively. one airbag is randomly selected for testing. if an airbag kills a passenger, calculate the probability that the airbag was manufactured by cool. (round to the nearest ten-thousandth.)
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Ответ:
Air bag manufactured by Aces(A)=57%
So, Probability![P(A)=\frac{57}{100}](/tpl/images/0063/8131/75088.png)
Air bag manufactured by Best (B) =26%
So, Probability![P(B)=\frac{26}{100}](/tpl/images/0063/8131/42e3a.png)
Airbag manufactured by Cool(C)=17%
So, Probability![P(C)=\frac{17}{100}](/tpl/images/0063/8131/3ad61.png)
Airbags made by Aces, Best, and Cool do not kill people at rates of 99%, 96%, and 87%, respectively.
Let K be the event which kill people.
Probability of Air bag made by A which kill people![P(K/A)=\frac{1}{100}](/tpl/images/0063/8131/2ee51.png)
Probability of Air bag made by B which kill people![P(K/B)=\frac{4}{100}](/tpl/images/0063/8131/657fa.png)
Probability of Air bag made by C which kill people![P(K/A)=\frac{13}{100}](/tpl/images/0063/8131/a471d.png)
If an airbag kills a passenger, calculate the probability that the airbag was manufactured by Cool
Using Baye's theorem:
Substitute the values of probabilities into formula
We get,
Now we calculate it and get probability
So,![P(C/K)=0.5785](/tpl/images/0063/8131/f21c7.png)
So, 57.85% of passenger kills if the airbag was manufactured by Cool.
Ответ:
why, what did he/she do?