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alisonlebron15
30.01.2020 •
Mathematics
Ajuggler throws a ball into the air, releasing it 5 feet above ground with an initial velocity if 15 fps. she catches the ball in thr other hand 5 feet above the ground. how long was the ball in the air?
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Ответ:
Here, you don't need to calculate velocity, but rather time. Start with this equation:
v = v0 + a t^2, where v is the velocity at time t, v0 is the initial velocity, a is the acceleration due to gravity (denoted by g instead of a), and t is the elapsed time.
You are told that v0 is 15 ft/sec. Set v = to 0, as the ball stops moving for the tiniest instant at the top of its trajectory. Use g = - 32 ft (per second squared).
Then 0 = 15 ft/sec - 32 [ft/(seconds squared)] t.
Solve this for t. This is the time required for the ball to come to a complete stop at the top of its trajectory.
Finally, multiply this time by 2, since the ball begins to fall and returns to its original height.
Ответ:
1206
I hope this helps lol