burritomadness
17.09.2019 •
Mathematics
Aladder 10 ft long rests against a vertical wall. if the bottom of the ladder slides away from the wall at a rate of 1.1 ft/s, how fast is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall? (that is, find the angle's rate of change when the bottom of the ladder is 8 ft from the wall.)
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Ответ:
X = the distance of the bottom of the ladder from the wall at any time
dX/dt = rate of travel of the bottom of the ladder = 1.1 ft/sec
A = the angle of the ladder with the ground at anytime
dA/dt = rate of change of the angle in radians per second
X = 10 cos A
dX/dt= -10 sin A dA/dt = 1.1
dA/dt = -1.1/(10 sinA)
When X = 6; cosA = 6/10; sinA = 8/10
Therefore:
dA/dt = -1.1/(10 x 0.8) = -0.1375 radiant per second.
Ответ: