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arletsolis23p2cjls
18.12.2019 •
Mathematics
Aladder is leaning against the very top of a building. the base of the ladder is 18 feet from the building and is leaning at a 60 degree angle. how tall is the building?
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Ответ:
The height of the building is 18
feet .
Step-by-step explanation:
Given as :
The distance of the base of ladder from building = d = 18 feet
The ladder is leaning at the angle = Ф = 60°
Let the height of the building = h feet
Now, From figure
Tan angle =![\dfrac{\textrm perpendicular}{\textrm base}](/tpl/images/0423/6702/a5d65.png)
Or,Tan Ф =![\dfrac{\textrm AB}{\textrm OA}](/tpl/images/0423/6702/b7eca.png)
Or,Tan 60° =![\dfrac{\textrm h}{\textrm 18}](/tpl/images/0423/6702/fb8db.png)
Or,
= ![\dfrac{\textrm h}{\textrm 18}](/tpl/images/0423/6702/fb8db.png)
∴ h = 18
feet
So, The height of the building = h = 18
feet
Hence, The height of the building is 18
feet . Answer
Ответ:
47 is 0.5 of 94
Step-by-step explanation:
0.5 x 2 = 1
47 x 2 = 94