Algebra 1 need help (Solving exponents equations)

Actually Welcome to the Concept of the exponents and indices.

here, we should remember one thing that,

3 ^3 = 27 and 1/3^x = 3^-x

so we get as,

(3^-3)^4-x = (3^3)^2x-1

==> 3^-12+3x = 3^6x-3

since the base is same that is 3 , we equate their powers.

-12x+3=6x-3

==> 3+3 = 6x+12x

==> 6 = 18x

hence ===> x = 6/18 = 1/3

hence, x = 1/3

when x=3: answer is 1

when x=0: answer is 1

when x=5: answer is 1

Step-by-step explanation:

Substitute the given value into the function and evaluate.

I hope this helped!!

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It's ok id u don't...lol