Mathematics: Algebra II: The 4th term of a geometric sequence is 48, and the common ratio is 2. What is the first term of the sequence? *There are no answer choices available on Kydor* Thank you so much for your help!

Algebra II: The 4th term of a geometric sequence - id413267141, tryintopassenioryear

Ответ:

cw1242605

15.06.2021

Step-by-step explanation:

$nth \: term \: of \: geometric \: \\ sequence \: is \: given \: as : \\ a_n = a {r}^{n - 1} \\ (a = ?, \: \: r = 2)\\ \\ a_4 =48......(given) \\ \\ \therefore \: a {(2)}^{4 - 1} = 48 \\ \\ \therefore \: a {(2)}^{3} = 48\\ \\ \therefore \: 8a = 48 \\ \\ \therefore \: a = \frac{48}{8} \\ \\ \therefore \:a = 6$

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Ответ:

kenishawilkinsoy4mgw

02.02.2020

Mathematics

8.038 * 10^8since the exponent is 8, start at ur decimal in 8.038 and count 8 spaces to the right
803,800,000

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Algebra II: The 4th term of a geometric sequence is 48, and the common ratio is 2. What is the first term of the sequence?

There are no answer choices available on Kydor

Thank you so much for your help!

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