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All composite numbers are multiples of other natural num

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Ответ:

Gattuso

30.10.2022

Mathematics

Hi.

Firstly, factorise the given numbers :

☆ 10 = 2 × 5

☆ 5 = $5^{1}$

☆ 13 = $13^{1}$

Then, count the number of times each prime factor appears in the factorization of all :

L.C.M = 2 × 5 × 13 = 130

Hence

$\boxed{\sf L.C.M = 130}$

Thanks!

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