zachtheskier3896
08.02.2020 •
Mathematics
All of the following are terminating decimals except
Solved
Show answers
More tips
- S Sport How does Bodyflex work: what is it and how does it work?...
- O Other What is the oldest joke ever told?...
- F Food and Cooking How to Make Lazy Cabbage Rolls? Simple Steps to a Delicious Dish...
- F Food and Cooking Unusually Delicious Shashlik - Follow the Etiquette of Proper Preparation!...
- L Leisure and Entertainment Couchsurfing: A New Way to Travel...
- G Goods and services Which TV is better - LCD or Plasma?...
- S Sport How to Learn to Pull Up on Monkey Bars?...
- L Leisure and Entertainment Scrapbooking: What is it and Why is it Becoming More Popular?...
- C Computers and Internet Where did torrents.ru move to?...
- B Business and Finance Understanding Cash Flow: What It Is and How It Works...
Answers on questions: Mathematics
- M Mathematics Help plz!! i need answers as soon as possible...
- M Mathematics Please help me fast ...
- C Computers and Technology : (Variable-Length Argument List) Write an application that calculates the product of a series of integers that are passed to method product using a variable-length argument list....
- M Mathematics 6,300,000,000 = 6.3 x 1,000,000,000 = 6.3 x 10 are they both in scientific notation...
- M Mathematics Solve using the quadratic formula...
Ответ:
answer:
except the odd
Ответ:
6 +2√3 ft²
Step-by-step explanation:
Given a triangular pyramid with ...
an equilateral triangular baselateral edge length 2 ftlateral area 6 ft²Find
total surface areaSolution
Since corresponding edges are the same length, the area of each of the three faces is (6 ft²)/3 = 2 ft². This can be computed by ...
A = (1/2)s²·sin(α)
where s is the lateral edge length and α is the angle at the apex formed by the two edges that meet there. Filling in the given values, we find ...
2 ft² = (1/2)(2 ft)²·sin(α)
1 = sin(α) ⇒ α = 90°
That is, each face of the pyramid is an isosceles right triangle with legs of length 2 ft. The hypotenuse of that triangle, the base edge of the pyramid, is then 2√2 ft.
So, the base is an equilateral triangle with edge lengths 2√2 ft. Its area can be computed from ...
A = (√3)/4·s²
where s is the edge length of the equilateral triangle. That is, the base area is ...
A = (√3)/4·(2√2)² = 2√3 . . . . square feet
So, the total surface area of the pyramid is ...
(6 +2√3) ft² ≈ 9.4641 ft² . . . . . total surface area