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bryamp4268
21.07.2019 •
Mathematics
All tutors that are employed at a local college must take a test and must score in the top 20%. if the scores are normally distributed with a mean of 78 and a standard deviation of 5, what is the cutoff score to be hired?
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Ответ:
To solve this problem, we use the z statistic with formula:
z = (x – u) / s
or
x = s z + u
First we find the value of z at P = top 20%
z = 0.84
So the cut-off is:
x = 5 * 0.84 + 78
x = 82.2 (ANSWER)
Ответ:
2 1/9 = 2.111
7/6 = 1.167
2.111-1.167= .944