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alexacarillo
28.01.2020 •
Mathematics
Aman bought a trampoline for his children to use. the trampoline has a diameter of 23 feet. if the man wishes to put up netting to go around the outside of the
trampoline, how many feet of netting does he need? give the exact circumference of the trampoline and then an approximation. use it 3.14
/
the exact circumference of the trampoline is on
(type an exact answer, using a as needed.)
/
/
the approximate circumference the trampoline is
(type a whole number or a decimal rounded to the nearest hundredth.)
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Ответ:
The exact circumference of the trampoline is 72.22 ft.
The approximate circumference the trampoline is 72 ft.
Step-by-step explanation:
The given diameter of the trampoline = 23 feet
Now , Diameter = 2 x RADIUS
⇒ R = D/2 = 23/2 = 11.5 ft
CIRCUMFERENCE of a CIRCLE = 2 π R
So, here the circumference of the trampoline = 2 x π x (11.5 )
= 2 x (3.14) x (11.5) = 72.22 ft
or, C = 72.22 ft
Now,as the decimal part is 0.22 which is LESS THAN 0.5
⇒ 72.22 ≈ 72 ft
Hence, The exact circumference of the trampoline is 72.22 ft.
The approximate circumference the trampoline is 72 ft.
Ответ:
16. x = 16.5
17. x =![33.1^o](/tpl/images/0329/8166/4a4b2.png)
Step-by-step explanation:
Problem 16: Use the tangent function of angle 36 degrees, since it relates opposite side (12) with adjacent side (x):
which rounded to the nearest tenth is: 16.5
Problem 17: Use the arcsin function to find the angle x, since sine relates opposite side with hypotenuse in a right angle triangle:
which rounded to the nearest tenth is: 33.1