pacangel
12.08.2019 •
Mathematics
Amanager of a large computer network has developed the following probability distribution of the number of interruptions per day: interruptions (x), p(x). 0, 0.32. 1, 0.35. 2, 0.18. 3, 0.08. 4, 0.04. 5, 0.02. 6, 0.01. compute the expected number of interruptions per day. compute the standard deviation.
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Ответ:
Step-by-step explanation:
Given that a manager of a large computer network has developed the following probability distribution of the number of interruptions per day
X denotes interruptions and P(X) probability
x*p(X)x^2p(x)
00.3200
10.350.350.35
20.180.360.72
30.080.240.72
40.040.160.64
50.020.10.5
60.010.060.36
Total11.273.29
Variance1.6771
std dev1.295028957
Expected value = sum of all products of x with corresponding p
= 1.27
Answer is 1.27
Std dev = sqrt of variance = 1.2950
Ответ:
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Step-by-step explanation: