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samueltaye
20.03.2020 •
Mathematics
An advertiser claims that the average percentage of brown M&M'S candies in a package of milk chocolate M&M'S is 14%. Suppose you randomly select a package of milk chocolate M&M'S that contains 51 candies and determine the proportion of brown candies in the package. (a) What is the approximate distribution of the sample proportion of brown candies in a package that contains 51 candies? The distribution is approximated by a normal distribution with mean 0.14 and standard deviation 0.0486. The distribution is approximated by a normal distribution with mean 0.14 and standard deviation 0.86. The distribution is approximated by a normal distribution with mean 7.1 and standard deviation 714. The distribution is approximated by a normal distribution with mean 14 and standard deviation 0.0486. The distribution is binomial and cannot be approximated. (b) What is the probability that the sample percentage of brown candies is less than 23%? (Round your answer to four decimal places.) (c) What is the probability that the sample percentage exceeds 32%? (Round your answer to four decimal places.) (d) Within what range would you expect the sample proportion to lie about 95% of the time? (Round your answers to two decimal places.) to
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Ответ:
4.66 pounds
Step-by-step explanation:
follow the following steps to calculate the standard deviation :
1. find the mean of the observations
2. subtract the mean from each observations
3. square the result gotten from the answers gotten in the previous step
4. Add each of the squares gotten above and divide by the number of observations
5. find the square root of the answer gotten in the above stage
check the attached images for an explanation of how the answer was derived.