magiflores6122
05.07.2019 •
Mathematics
An airplane is flying 38,900 ft above the ground. angle of depression from the plane to the base of the building is 4.3°. how far must a plane fly horizontally to be directly over the building?
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Ответ:
Height of the airplane above the ground = 38,900 ft.
Angle of depression from the plane to the base of the building = 4.3°.
So, we could apply tangent trigonometric ratio:
tan 4.3° =
0.07519 =
On cross multiply, we get
0.07519 x= 38,900.
Dividing both sides by 0.07519, we get
x= 517356.03 ft.
Therefore, the plane must fly 517356.03 ft. horizontally to be directly over the building.Ответ:
x = 16
Step-by-step explanation:
2x + (3x-6) = 74
5x -6 = 74
5x = 74 + 6
5x = 80
x = 16