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devin030505
25.07.2019 •
Mathematics
An airplane leaves the airport at 2 pm and travels 650 mph to its destination. a second plane leaves at 6 pm and travels 800 mph. how long before the second plane reaches the same distance as the first plane?
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Ответ:
P1 at 2pm rate of 650m/h
P2 at 6pm rate of 800m/h
difference of 4 hrs, means 4 hrs x 650m/h = 2600miles difference when P2 leaves.
assuming both planes are instantaneously at their speeds...
800m/h = 2600miles + 650m/h
-650m/h. -650m/h
150m/h = 2600miles
÷150. ÷150
=17.33 hours
= 17 hours and 20 minutes. This is putting 2 linear equations equal to each other.
Ответ:
C
Step-by-step explanation: