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sonyav732
19.12.2019 •
Mathematics
An engineer who is studying the tensile strength of a steel alloy intended for use in golf club shafts knows that tensile strength is approximately normally distributed with σ=75 psi. a random sample of 12 specimens has a sample mean tensile strength of 3450 psi. is there evidence to support the claim that mean strength is greater than 3400 psi. state and test the hypothesis at significance level α =0.01. (2 points)
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Ответ:
We conclude that the mean strength is equal to 3400 psi.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 3400 psi
Sample mean,
= 3450 psi
Sample size, n = 12
Alpha, α = 0.051
Population standard deviation, σ =75 psi
First, we design the null and the alternate hypothesis
We use one-tailed(right) z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We fail to reject the null hypothesis and accept the null hypothesis. Thus, we conclude that the mean strength is equal to 3400 psi.
Ответ:
Answers:
===================================================
Explanation:
Replace x in f(x) with 2. Then simplify
Then plug x = 1 into the inverse function and simplify
Lastly,
is the result of combining the two parts above.