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krystalhurst97
28.09.2019 •
Mathematics
An equation of the line that contains the origin and the point (1,3) is
a) y=3x+1
b) y/3=x-1
c) y=3x
d) y=c-1
e) 3y=x
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Ответ:
y = mx + c
where
m = slope
c = y-intercept
The line passes through the origin (0,0), therefore
0 = m*0 + c => c = 0
Therefore the equation is of the form
y = mx
The line passes through (1,3). Therefore
3 = m*1 => m = 3.
The equation for the line is
y = 3x
C) y=3x
Ответ:
23456789
Step-by-step explanation: