meg12331
20.10.2020 •
Mathematics
An honest coin is tossed 4 times in a row. Find the probability of each of the following events. (a) E1: "The coin comes up tails exactly twice." (b) E2: "All 4 tosses come up the same." (c) E3: "Exactly one-third of the tosses come up ." (d) E4: "The first 2 tosses come up heads ."
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Ответ:
3/8 ; 1/8 ; 0 ; 1/4
Step-by-step explanation:
Given that:
For a coin toss :
Sample space = {HHTT, HTTT, THTT, , HHHT, HTHT, THHT, TTHT, HHTH, HTTH, THTH, TTTH, , HTHH, THHH, TTHH}
Probability = required outcome / Total possible outcomes
a) E1: "The coin comes up tails exactly twice."
p(E1) = 6/16 = 3/8
(b) E2: "All 4 tosses come up the same."
{, }
p(E2) = 2/16 = 1/8
(c) E3: "Exactly one-third of the tosses come up head."
1/3 of 4 ; p = 0 ; outcome is not a whole number
(d) E4: "The first 2 tosses come up heads ."
P(E4) = 4/16 = 1/4
Ответ:
Im confused on what ur trying to say
Step-by-step explanation: