antwain2

25.01.2020 • 

Mathematics

An insurance company claims that in the entire population of homeowners, the mean annual loss from fire is --$250 and the standard deviation of the loss is ơ-$1000. the distribution of losses is strongly right-skewed: many policies have $0 loss, but a few have large losses. an auditor examines a random sample of 10,000 of the company's policies. if the company's clairm is correct, what's the probability that the average loss from fire in the sample is no greater than $275?

Ответ:

rimcdaniel2

16.01.2022

Mathematics

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the probability that the average loss from fire in the sample is no greater than $275 is 0.9938

Step-by-step explanation:

given information:

mean, μ = $250

std deviation, σ = $1000

random sample, n = 10000

x = $275

P( ∠_ 275) = P(z < (z ∠ (x - μ)/(σ/√n))

                    = P (z ∠ (275 - 250)/(1000/√10000)

                    = P(z ∠ 2.5)

                     =  0.9938

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Ответ:

rostecorralmart

06.09.2020

Mathematics

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well I would write it as a fraction so I think it would be 6/8 because the are altogether 8 and the probability of it not being a hobbit or an umbrella is 6 you count all of the characters except hobbit and then you count all of the tools except an umbrella and that gives you 6 so it is 6/8. hope that helped:]

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