roseemariehunter12

06.03.2021 • 

Mathematics

An object is launched at 39.2 meters per second (m/s) from a 42.3-meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t^{2} + 39.2t + 42.3, where s is in meters. Create a table of values and graph the function. Approximately when will the object hit the ground?

Ответ:

treylartigue

21.04.2021

Mathematics

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200 feet = 200 * 0.3048 = 60.96 m
e = 0.5 * g * t ^2
e = 60.96
g = 9.8 m/s2
t = ?
t^2= 60.96 / 0.5 * 9.81 = 12.440
t = 3.5271 s

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Ответ:

laurenrubin18

22.11.2021

Mathematics

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V=S(base)*h=pi*r2
V=pi*r2*h
V=3,14*(half of diameter in square)8,75in square*16,5
V=3,14*8,75(in square)*16,5in
===3966,7
This is correct☺️

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