ctyrector

02.03.2020 • 

Mathematics

An object is propelled off of a platform that is 75 feet high at a speed of 45 feet per second (ft./s). The height of the object off the
ground is given by the formula h(t)= - 16t^2 + 45t + 75, where h(t) is the object's height at time (t) seconds after the object is propelled. The downward negative pull on the object is represented by - 16t^2. Solve for t.

Ответ:

thedocgalloway

27.07.2021

Mathematics

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arrange the equation first

3y=5x-14

divide by 3

y=(5/3)x-(14/3)

y-intercept= -14/3

X-intercept

put Y = 0

x=(14/3)(3/5)

x=14/5

Step-by-step explanation:

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