serianmollel
06.06.2020 •
Mathematics
An urn contains 5 are red balls and 6 blue balls. Suppose 5 are randomly selected without replacement. What is the probability that exactly 3 are red? Answer correct to four decimal places.
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Ответ:
27.94%
Step-by-step explanation:
The statement tells us that we have 5 red balls and 6 blue balls, that is, there are 11 in total (5 + 6)
So the probability of red balls = 5/11 and blue balls probability = 6/11
Let X be the number of red balls of those 5 selected balls.
Then X follows a binomial distribution with the following parameters:
n = 5
p = 5/11
q = 6/11
P (X) = nCx * p ^ (x) * q ^ (n -x)
required probability is P (X = 3), replacing:
P (X = 3) = 5C3 * (5/11) ^ (3) * (6/11) ^ (5 -3)
P (X = 3) = 5! / (3! (5-3)!) * 0.02794
P (X = 3) = 10 * 0.02794
P (X = 3) = 0.2794
Which means that the probability is 27.94%
Ответ:
im-
Step-by-step explanation: