Another graph i need with. i can find j'(2) and j'(3), but not j'(1). can someone ?

J'(1) = -4/3



if 

   

then we can differentiate using the quotient rule:

   

these graphs consist of linear funtions; we can get the values of their derivatives by using the slope of the graph at a point.

for  we have

   

because at  , the slope of the graph of  can be viewed as 3 (rise) over 2 (run).
the slope of  can be viewed as -1 (rise) over 2 (run).

note that 1/5 = 3/2

so with that information, we can calculate j'(1):

   

j'(1) = -4/3

Please answer please please thank you