Answer asap
javier has 3 bags that contained numbered balls.
bag a has balls numbered 1 to 3.
bag b has balls numbered 4 to 6.
bag c has balls numbered 7 to 9.
javier and his friend mayling make diagrams to represent all the possible outcomes if javier pulls one ball from each bag. however, when they compared diagrams, they realized that their diagrams were different.
which diagram shows the correct sample space if javier draws one ball from each bag?
using the correct diagram, how many outcomes are there where at least two balls show an odd number? [8, 16, 10, 12]
using the correct diagram, how many outcomes are there where just one ball is a multiple of 4? [12, 9, 15, 6]

Javier,16,12

Step-by-step explanation:

From the first bag, we can pull a 1,2 or 3.  That would go on the first line of the tree diagram

From the 2nd bag, we can draw a 4,5, or 6.  That goes on the the second line under each number

From the 3rd bag, we can draw a 7,8, or 9.  That goes on the the third line under each number

Javier drew the correct tree diagram.

1,3,5,7,9 are odd numbers.  We must have at least 2 of these numbers

1,4,7            2,5,7            3,4,7

1,4,9            2,5,9            3,4,9

1,5,7                                 3,5,7

1,5,8                                  3,5,8

1,5,9                                  3,5,9

1,6,7                                  3,6,7

1,6,9                                  3,6,9

There are 16 total where there are at least two odd numbers

Multiples of 4 are 4 and 8

We must have either a 4 or an 8 but not both

1,4,7             2,4,7         3,4,7

1,4,9            2,4,9          3,4,9

1,5,8            2,5,8          3,5,8

1,6,8            2,6,8          3,6,8

There are 12 outcomes

For this case we must solve the following equation:

Since the denominators on the right side of the equation are equal, then we add the fractions:

We subtract on both sides of the equation:

Thus, the value of p is 1.