![hannacarroll3670](/avatars/22542.jpg)
hannacarroll3670
09.02.2021 •
Mathematics
?
answer choices;
A. 1/5
B. 1/10
C. 1/2
D. 2/5
Solved
Show answers
More tips
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- H Health and Medicine Headache: A Comprehensive Guide to Treatment...
- C Computers and Internet How to Properly Order Clothing from International Online Stores...
- A Auto and Moto Mastering One-Movement Parking: All You Need to Know...
- D Dating, Love, Relationships How Long Can Love Last?...
- S Society and Politics Is It Fact or Fiction? Let s Talk About Anton Chekhov s Pseudonym...
- F Food and Cooking How to Find Your Zip Code?...
- S Style and Beauty How to choose the best mascara for your eyelashes...
- S Style and Beauty How to Apply Foundation Correctly?...
- S Sport How to Choose Tennis Rackets?...
Answers on questions: Mathematics
- M Mathematics If 7 - y = 6, then y = A. -29 B. -5 C. 1 D. 29...
- M Mathematics Will give brainliest f(x) = 2x - 4 g(x) = 4x + 5 Find (fºg)(x)...
- M Mathematics A ball is kicked from the ground at a velocity of 70 feet per second. 1. Write a function, g(t), to describe the height of the ball in terms of time t for the situations...
- M Mathematics Let ADOT-APAN. Find the missing side x Help pls...
- M Mathematics What is the answer to negative 2 over 9 subtracted by negative 1...
- H History Finally, do you remember this cartoon (if you are unable to access the cartoon, try University of Kent: Rendezvous) from the last unit? Explain why you think that...
- A Arts What according to you true friendship is?...
- M Mathematics I know the picture at the top is small so I’ll post another that only has that picture so you can see it closer...
Ответ:
Ответ:
c
Step-by-step explanation:
Ответ:
see explanation
Step-by-step explanation:
given
x + 4 =
( square both sides )
(x + 4)² = x + 10
x² + 8x + 16 = x + 10
rearrange into standard form : ax² + bx + c = 0
subtract x + 10 from both sides
x² + 7x + 6 = 0 ← in standard form
(x + 1)(x + 6) = 0 ← in factored form
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x + 6 = 0 ⇒ x = - 6
As a check
substitute these values into the equation and if the left side equals the right side then they are solutions
x = - 1 : left = - 1 + 4 = 3 , right =
=
= 3
Hence x = - 1 is a solution
x = - 6 : left = - 6 + 4 = - 2 , right =
=
= 2
Hence x = - 6 is an extraneous solution