Any smart people out there, i really suck at these five times lauren's age, decreased by 2 is equal to two times lauren's age, increased by 11. how old is lauren?

Set Lauren's age equal to L.

Using what the problem gave us, we can quickly set up an equation: 

5L - 2 = 2L

Solving this equation, we get 3L = 2. L = 2/3 Lauren is 2/3 of a year old.

Take it slowly, one step at a time.

First, you need to pick something to call "Lauren's age",
because you don't know what number it is.  I have a bright idea ! 
Let's call Lauren's age ' L ' !  OK ?

Use ' L ' to build the quantities discussed in the question:

Five times Lauren's age . . . . . . . . . . . . . . . . . 5 L
Five times Lauren's age, decreased by 2 . . . 5L - 2

Two times Lauren's age . . . . . . . . . . . . . . . . .  2 L
Two times Lauren's age, increased by 11 . . . 2L + 11

The question says that these 2 quantities are equal,
so write that down:
                                                      5L - 2  =  2L + 11

Add  2  to each side:                  5L        =  2L + 13

Subtract  2L  from each side:    3L        =           13

Divide each side by  3 :                L        =           13/3  or  4 and 1/3 .

That's certainly a weird number, but you can
check it out, and you'll find that it's true:

Lauren's age . . . . . 13/3

Five times Lauren's age . . . . . . . . . . . . . . . . . 65/3
Five times Lauren's age, decreased by 2 . . . 59/3    <===

Two times Lauren's age . . . . . . . . . . . . . . . . .  26/3
Two times Lauren's age, increased by 11 . . . 59/3    <===

Those 2 quantities are equal.  So Lauren is 4-1/3 years old, by golly !

Step-by-step explanation:

Okay so Itś been awhile since I did this, but domain is all possible x-values and the range is all possible y-values.  But I do not think that 0 is included.

The domain would be: -1 and 1

The range would be: 7, -3, 10, and 7

Honestly I have no idea what the function is sorry love :\