anaikad
04.10.2019 •
Mathematics
Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). her work is shown below.
let (x2, y2) be (–7, 4) and (x1, y1) be (2, –3).
m = m equals startfraction x 2 minus x 1 over y 2 minus y 1.
= equals startfraction negative 7 minus 2 over 4 minus negative 3.
= equals negative startfraction 9 over 7.
the slope is negative startfraction 9 over 7 endfraction..
what error did she make?
a) she simplified the denominator incorrectly. the denominator simplifies to –7.
b) she labeled the points incorrectly. the point (–7, 4) should be (x1, y1).
c)she used an incorrect formula. the formula should be the change in y-values with respect to the change in the x-values.
d) she used an incorrect formula. the formula should be the sum of the x-values with respect to the sum of the y-values.
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Ответ:
C)She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values.
Step-by-step explanation:
When finding the slope of a line, the formula is rise over fall.This means the change in y divided by the change in x
Given that x₁y₁ is (2,-3) and x₂,y₂ is (-7,4) then
The change is y, Δy = (y₂-y₁) = (4--3) = 7
The change is x, Δx = (x₂-x₁) = (-7-2)= -9
The slope is - 7/9 and not -9/7
Ответ:
5√2 or 3 and 2
Step-by-step explanation:
You would bring it down for 9 and 8 which would be 72
Then you would get a perfect square of 9 which would be 3
Then you would do 4*2 which would be 8 so you would divide 4 by 2 which would be two which would be another perfect score.
So then you would add them which would be 5 then you get the leftover 2 and make 5√2
But your perfect squares are 3 and 2