Anyone know the answer to this

Part A:

- angle ACB= 60° (ABC equilateral triangle.)

- Angle ECD=EDC= (180°-32°)/2= 148/2= 74° (sum of angles in a triangle is equal to 180, and triangle ECD is isosceles since it's given that CE=DE.

- x= 180°-(60°+74°)

   = 180°-134°

   = 46°

x= 46°

Part B:

120°

Vertex Form: f(x) = (x - 4)² + 1

Standard Form: f(x) = x² - 8x + 17

Step-by-step explanation:

Standard Form: ax² + bx + c = 0

Transformations Graph: f(x) = a(bx - c)ⁿ + d

a = vertical shrink/stretch

b = horizontal shrink/stretch

c = horizontal movement left/right

d = vertical movement up/down

(c, d) is vertex

Step 1: Define variables

Vertex (4, 1)

c = 4

d = 1

(Since we are dealing with a quadratic) n = 2

Step 2: Set up equation

f(x) = a(x - 4)² + 1

Step 3: Find a (vertical shrink/stretch)

Order of Operations: BPEMDAS

Point (3, 2) on given graph

Plug in the point to find a.

Substitute:                     2 = a(3 - 4)² + 1Parenthesis:                  2 = a(-1)² + 1Exponents:                    2 = a(1) + 1Multiply:                        2 = a + 1Solve:                            a = 1

Step 4: Write Vertex Form

f(x) = 1(x - 4)² + 1

f(x) = (x - 4)² + 1

Step 5: Convert to Standard Form

Define:                                     f(x) = (x - 4)² + 1Expand:                                    f(x) = x² - 8x + 16 + 1Combine like terms:                f(x) = x² - 8x + 17

Step 5: Check

Graph the newly founded equation.