Mathematics: Aperson is to install five devices each 6 and 7/8 inches wide with 3 1/2 inches between switches. how much space will be needed to mount these switches?

Aperson is to install five devices each 6 and 7/8

Ответ:

bloodry

08.01.2022

Mathematics

$34\frac{3}{8}\ in$

Step-by-step explanation:

we know that

To find out how much space will be needed to mount these switches, multiply the number of devices by the wide of each device plus the distance between switches multiplied by 4 (number of devices minus 1)

$5(6\frac{7}{8})+4(3\frac{1}{2})$

Convert mixed number to an improper fraction

$6\frac{7}{8}\ in=\frac{6*8+7}{8}=\frac{55}{8}\ in$

$3\frac{1}{2}\ in=\frac{3*2+1}{2}=\frac{7}{2}\ in$

substitute the values in the expression above

$5(\frac{55}{8})+4(\frac{7}{2})$

$(\frac{275}{8})+14$

$\frac{275+112}{8}$

$\frac{387}{8}\ in$

convert to mixed number

$\frac{387}{8}\ in=\frac{384}{8}+\frac{3}{8}=34\frac{3}{8}\ in$

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Ответ:

peytonwilson2003

09.06.2021

Mathematics

in English asse ine English

Step-by-step explanation:

because it has the right balance for all are things to solve in this situation is going into this no one thing that we all want is not going into effect or that it can

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Aperson is to install five devices each 6 and 7/8 inches wide with 3 1/2 inches between switches. how much space will be needed to mount these switches?

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