Apoint p has coordinates (–5, 4). what are its new

Ответ:

allisonchorath6971

29.10.2022

Step-by-step explanation:

Given is the equation

$\sqrt{x+3} -\sqrt{2x-1} =-2$

To solve this first we take II term to right side and then square

Step I:Simplify to obtain final radical sign on one side

$sqrt{x+3}=-\sqrt{2x-1} -2$

Step 2: raise to power 2

$x+3 ={2x-1} +4+4\sqrt{2x-1}$

Step 3:

Simplify to get a quadratic equation

-x=4\sqrt{2x-1}[/tex]

Square both sides

$x^2=16(2x-1)\\x^2-32x+16=0\\$

Step 4: Use quadratic formula to find roots

$x=\frac{32±\sqrt{32^2-64} }{2} \\x=16±4\sqrt{15}$

So answer is the above.

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