Apool in the shape of a rectangle has a perimeter of 80feet. the pool is 8 feet less wide than it is long. find the length and width of the pool

The length and width of the pool = 24 ft and 16 ft

Step-by-step explanation:

Let length of pool be l and width of pool be w.

A pool in the shape of a rectangle has a perimeter of 80feet.

Perimeter of pool = 2 x ( l + w ) = 80 feet

That is

       l + w  = 40 ft eqn 1.

The pool is 8 feet less wide than it is long.      

      l = 8 + w

       l - w  = 8 ft eqn 2.      

eqn 1 + eqn 2

        2 l = 48

         l = 24 ft

Substituting

         24 + w = 40

         w = 16 ft

The length and width of the pool = 24 ft and 16 ft

Perimeter is P = 2L + 2W, with L being length and W being width.  If the perimeter is 80, we have the P for our equation.  It tells us that the width is  feet less than the length, so W = L - 8.  We will fill that into our perimeter equation to solve for L.  80 = 2L + 2(L-8).  80 = 2L + 2L - 16.  64 = 2L + 2L , and 64 = 4L.  That means that the length is 16.  The width is 8 less than that, so the width is 8.  There you go!

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